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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In △ABC,a:b:c=(1+x):1:(1−x)\triangle A B C, a: b: c=(1+x): 1:(1-x), where x∈(0,1)x \in(0,1). If ∠A=π2+∠C\angle A=\frac{\pi}{2}+\angle C, then xx is equal to
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Correct option: C
17\frac{1}{\sqrt{7}}
Option C (17\frac{1}{\sqrt{7}}) is correct because it is the value of x that satisfies the given conditions and trigonometric relationships in the triangle.

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