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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1
dxdy=1+x−y2y\frac{d x}{d y}=\frac{1+x-y^2}{y} and x(1)=1x(1)=1, then 5x(2)5 x(2) is equal to
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Correct option: A
5
Option A (5) is correct because solving the differential equation and applying the given condition x(1)=1, we find x(2) = 1, and thus 5x(2) = 5.

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