NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Easy

1 of 1

Application +4 | -1

For the melting of

NaCl

heat required is

7.26\,K\,cal\,mo{l^{ - 1}}

and

\Delta S

increases by

6.73\,cal\,mo{l^{ - 1}}.{K^{ - 1}}.

The melting point of the salt is

View answer and explanation

Correct option: A

805.75^\circ C

Option A (

805.75^\circ C

) is correct because the melting point is calculated using the formula

T = \frac{{\Delta H}}{{\Delta S}}

and then converted from Kelvin to Celsius.

More Questions from THERMODYNAMICS

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{T_i}

{T_f}

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

\Delta G