JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

The point on the curve

y = {x^3}

at which the tangent to the curve is parallel to the

x

-axis, is

View answer and explanation

Correct option: D

(0,0)

Option D ((0,0)) is correct because the tangent is parallel to the x-axis when the derivative dy/dx is zero, which occurs at x=0 for the given curve.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z