One of the square root of $6 + 4\sqrt 3 $ is

$\sqrt 3 \left( {\sqrt 3 + 1} \right)$

$ - \sqrt 3 \left( {\sqrt 3 - 1} \right)$

$\sqrt 3 \left( { - \sqrt 3 + 1} \right)$

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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

One of the square root of

6 + 4\sqrt 3

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Correct option: D

None of these

Option D (None of these) is correct. The square root of 6 + 4√3 cannot be expressed in the form √x + √y where x and y are rational numbers, as the discriminant becomes negative.

More Questions from COMPLEX NUMBERS

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The number of non-zero integer solutions of the equation

{\left| {1 - i} \right|^x} = {2^x}

is If

|z|=1

and

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, then for any complex number

z, \frac{z}{1-z^2}

Let

\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

, then

\left|\sum\limits_{r=1}^n z_r\right|

is less than The roots of the cubic equation

(z+a b)^3=a^3

, where

a \neq 0

represents the vertices of a triangle. If

\alpha, \beta

and

\gamma

are the roots, then find the value of

|\alpha-\beta|

. Number of solutions of the equation

{z^2} + {\left| z \right|^2} = 0,

where

z \in C

is If

2x = - 1 + \sqrt 3 i

, then the value of

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}

is equal to