The integral $\int {{{\sec }^{2/3}}x\,{\rm{cose}}{{\rm{c}}^{4/3}}x\,dx} $ is equal to (here $C$ is a constant of integration)

$ - \frac{3}{4}{\tan ^{ - 4/3}}x + C$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

The integral

\int {{{\sec }^{2/3}}x\,\mathrm{cose}{\mathrm{c}^{4/3}}x\,dx}

is equal to (here

C

is a constant of integration)

View answer and explanation

Correct option: B

- 3{\tan ^{ - 1/3}}x + C

Option B (

- 3{\tan ^{ - 1/3}}x + C

) is correct because the integral evaluates to this expression after substitution and simplification.