A body cools down from $50^{\circ} \mathrm{C}$ to $45^{\circ} \mathrm{C}$ in $5 \mathrm{~min}$ and $45^{\circ} \mathrm{C}$ to $40^{\circ} \mathrm{C}$ is $8 \mathrm{~min}$. Find the temperature of the surrounding. Assume Newton's law of cooling is valid.

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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A body cools down from

50^{\circ} \mathrm{C}

45^{\circ} \mathrm{C}

5 \mathrm{~min}

and

45^{\circ} \mathrm{C}

40^{\circ} \mathrm{C}

8 \mathrm{~min}

. Find the temperature of the surrounding. Assume Newton's law of cooling is valid.

View answer and explanation

Correct option: A

34^{\circ} \mathrm{C}

Option A (

34^{\circ} \mathrm{C}

) is correct because it is the solution to the system of equations derived from Newton's Law of Cooling.