JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

1 Easy

1 of 1

Application +4 | -1

Calculate radiation power for sphere whose temperature is

227^{\circ} \mathrm{C}

and radius

0.2

and emissivity

0.8.

View answer and explanation

Correct option: A

1425 \mathrm{~W}

Option A (

1425 \mathrm{~W}

) is correct because it is calculated using the Stefan-Boltzmann law:

P = \sigma A e T^4

More Questions from THERMAL PROPERTIES OF MATTER

Practice All Chapter MCQs →

n = \frac{{PV}}{{RT}},n =

{25^0}

{0^0}C

E\,\,W{m^{ - 2}}

\left( {\frac{T}{2}} \right)K