JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Hard

1 of 1

Application +4 | -1

Let

{x^2} + {y^2} + Ax + By + C = 0

be a circle passing through (0, 6) and touching the parabola

y = {x^2}

at (2, 4). Then

A + C

is equal to ______.

View answer and explanation

Correct option: A

Option B (96) is correct because it is the solution to the system of equations derived from the given information about the arithmetic progression.

More Questions from TANGENTS & NORMALS

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z