If $y = a{x^{n + 1}}$, then ${x^2}\frac{{{d^2}y}}{{d{x^2}}}$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Hard

1 of 1

Application +4 | -1

y = a{x^{n + 1}}

, then

{x^2}\frac{{{d^2}y}}{{d{x^2}}}

is equal to

View answer and explanation

Correct option: B

n\left( {n + 1} \right)y

Option B (

n\left( {n + 1} \right)y

) is correct because it is the result of calculating the second derivative and multiplying by

x^2

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\lim \limits_{{x \rightarrow \infty}} y(t)