Domain of the function $f\left( x \right) = \sqrt {2 - 2x - {x^2}} $ is

$ - \sqrt 3 \le x \le + \sqrt 3 $

$ - 2 + \sqrt 3 \le x \le - 2 - \sqrt 3 $

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Domain of the function

f\left( x \right) = \sqrt {2 - 2x - {x^2}}

View answer and explanation

Correct option: B

- 1 - \sqrt 3 \le x \le - 1 + \sqrt 3

Option B (

- 1 - \sqrt 3 \le x \le - 1 + \sqrt 3

) is correct because it represents the interval where the quadratic expression inside the square root is non-negative.

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