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JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

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Application +4 | -1
Orthocentre of the △ABC\triangle A B C, where A≡(acos⁡θ1,asin⁡θ1),B≡(acos⁡θ2,asin⁡θ2)A \equiv\left(a \cos \theta_1, \mathrm{a} \sin \theta_1\right), B \equiv\left(a \cos \theta_2, a \sin \theta_2\right) and C≡(acos⁡θ3,asin⁡θ3)C \equiv\left(a \cos \theta_3, a \sin \theta_3\right) is
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Correct option: C
(aΣcos⁡θ1,aΣsin⁡θ1)\left(\mathrm{a} \Sigma \cos \theta_1, \mathrm{a} \Sigma \sin \theta_1\right)
Option C ((aΣcos⁡θ1,aΣsin⁡θ1)(a \Sigma \cos \theta_1, a \Sigma \sin \theta_1)) is correct because the orthocenter of a triangle inscribed in a circle with center at the origin is given by the sum of the vertices.

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