If $\frac{{dy}}{{dx}} + y = 2{e^{2x}}$, then $y$ is equal to

$\left( {1 + x} \right){e^{ - x}} + \frac{2}{3}{e^{2x}} + c$

${e^{ - x}} + \frac{2}{3}{e^{2x}} + c$

JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1

\frac{{dy}}{{dx}} + y = 2{e^{2x}}

, then

y

is equal to

View answer and explanation

Correct option: C

c{e^{ - x}} + \frac{2}{3}{e^{2x}}

Option C (

c{e^{ - x}} + \frac{2}{3}{e^{2x}}

) is correct because it is the solution to the given first-order linear differential equation obtained using the integrating factor method.

Practice All Chapter MCQs →

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