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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
If ∫(x2−1)dx(x4+3x2+1)tan⁡−1x2+1x=\int \frac{\left(x^2-1\right) \mathrm{d} x}{\left(x^4+3 x^2+1\right) \tan ^{-1} \frac{x^2+1}{x}}= log⁡∣tan⁡−1f(x)∣+C\log \left|\tan ^{-1} f(x)\right|+C then
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Correct option: D
f(x)=x2+1xf(x)=\frac{x^2+1}{x}
Option D (f(x)=x2+1xf(x)=\frac{x^2+1}{x}) is correct because after dividing the numerator and denominator by x2x^2 and using appropriate substitutions, the integral simplifies to log⁡∣tan⁡−1(x2+1x)∣+C\log |\tan^{-1} (\frac{x^2+1}{x})| + C.

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