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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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The length of a needle floating on water is 2.5 cm2.5 \mathrm{~cm}. How much minimum force, in addition to the weight of the needle, will be needed to lift the needle above the surface of water? Surface tension of water =7.2×10−4 Ncm−1=7.2 \times 10^{-4} \mathrm{~Ncm}^{-1}.
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Correct option: A
3.6×10−3 N3.6 \times 10^{-3} \mathrm{~N}
The correct answer is A (3.6×10−3 N3.6 \times 10^{-3} \mathrm{~N}) because the force needed to lift the needle is calculated using the surface tension and the length of contact.

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