JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

Range of the function,

f(x)=\frac{\left(1+x+x^2\right)\left(1+x^4\right)}{x^3}

, for

x>0

is:

View answer and explanation

Correct option: D

[6, \infty)

Option D ([6, ∞)) is correct because the minimum value of the function is 6, found by applying AM-GM inequality.

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f\left( x \right) = x - \left[ x \right]

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S=\left\{x: f(x)=f^{-1}(x)\right\}