JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

z

is a complex number such that

|z| \geq 2

, then the minimum value of

\left|z+\left(\frac{1}{2}\right)\right|

, is

View answer and explanation

Correct option: D

lies in the interval

(1,2)

The correct answer is D (lies in the interval (1,2)) because the minimum value of

|z + (1/2)|

occurs when

z

is on the circle

|z| = 2

and closest to

-1/2

, resulting in a value of 3/2, which lies in the interval (1,2).

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