JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Easy

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Application +4 | -1

Two particles whose masses are

10 \mathrm{~kg}

and

30 \mathrm{~kg}

and their position vectors are

\hat{i}+\hat{j}+\hat{k}

and

-\hat{i}-\hat{j}-\hat{k}

respectively would have the centre of mass at

View answer and explanation

Correct option: A

-\frac{(\hat{i}+\hat{j}+\hat{k})}{2}

Option A (

-\frac{(\hat{i}+\hat{j}+\hat{k})}{2}

) is correct because it is the calculated center of mass position vector of the two particles.

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\mathrm{AB}

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\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)