JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

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Analyzing +4 | -1

|z-2-i|=|z|\left|\sin \left(\frac{\pi}{4}-\arg z\right)\right|

, where

i=\sqrt{-1}

, then locus of

z

, is

View answer and explanation

Correct option: C

parabola

Option C (parabola) is correct because the given equation represents a parabola when converted to Cartesian coordinates.

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{\left| {1 - i} \right|^x} = {2^x}

|z|=1

z \neq \pm 1

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\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

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