If $P$ is a point in space such that $O P$ is inclined to $O X$ at $45^{\circ}$ and $O Y$ to $60^{\circ}$ then $O P$ is inclined to $O Z$ at

JEE MATHEMATICS MCQ: DCS AND DRS

1 Easy

1 of 1

Application +4 | -1

P

is a point in space such that

O P

is inclined to

O X

45^{\circ}

and

O Y

60^{\circ}

then

O P

is inclined to

O Z

View answer and explanation

Correct option: B

60^{\circ}

and

120^{\circ}

Option B is correct because the angle to OZ is found using the relationship between direction cosines and the given angles to OX and OY.

Practice All Chapter MCQs →

\frac{2-x}{3}=\frac{3 y-2}{4 \lambda+1}=4-z

\frac{x+3}{3 \mu}=\frac{1-2 y}{6}=\frac{5-z}{7},

4 \lambda+9 \mu

\frac{x}{2}=\frac{y}{2}=\frac{z}{1}

\frac{x+2}{-1}=\frac{y-4}{8}=\frac{z-5}{4}

4 {~m}

2 {~kg}

10 {~kg}

45^{\circ}

60^{\circ}

X

Y

Z

\mathrm{AB}

-2 / \sqrt{17}

3 / \sqrt{17},-2 / \sqrt{17}

\mathrm{AB}=\sqrt{17}

\mathrm{A}

(3,-6,10)

\mathrm{B}

A B

45^{\circ}

120^{\circ}

X

Y

A B

\theta

Z

\theta