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NEET UG PHYSICS MCQ: ALTERNATING CURRENT

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In an ac circuit V   and   IV\,\,\,{\text{and}}\,\,\,I are given by V=50  sin⁡  50 t   voltV = 50\,\,\sin \,\,50\,t\,\,\,{\text{volt}} and I=100  sin⁡(50t+π3)  mA.I = 100\,\,\sin \left( {50t + \frac{\pi }{3}} \right)\,\,{\text{mA}}. The power dissipated in the circuit is
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Correct option: A
1.25 watt
Option A (1.25 watt) is correct because the power dissipated in an AC circuit is given by P=VrmsIrmscos⁡ϕP = V_{rms} I_{rms} \cos{\phi}, where ϕ\phi is the phase difference between voltage and current.

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