JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Analyzing +4 | -1

The interval in which the function

y = \frac{{x - 1}}{{{x^2} - 3\;x + 3}}

transforms the real line is

View answer and explanation

Correct option: D

\left[ { - 1/3,1} \right]

The correct answer is D ([-1/3, 1]) because this interval represents the range of the given function.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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S=\left\{x: f(x)=f^{-1}(x)\right\}