JEE CHEMISTRY MCQ: S-BLOCK ELEMENTS

1 Medium

1 of 1

Analyzing +4 | -1

{BeCl}_2

and

{AlCl}_3

are useful as catalysts in Friedel-Crafts reaction.

R:

{BeCl}_2

and

{AlCl}_3

provide

{Cl}^{+}

easily.

View answer and explanation

Correct option: A

Both A and R are true and R is the correct explanation of A

Option A (Both A and R are true and R is the correct explanation of A) is correct because both

{BeCl}_2

and

{AlCl}_3

act as Lewis acids in Friedel-Crafts reactions by providing

{Cl}^{+}

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\mathrm{K}_2 \mathrm{CrO}_4

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\mathrm{NH}_4 \mathrm{OH}

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\mathrm{KCl}

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