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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

If a spring of mass

30 \mathrm{~kg}

has spring constant of

15 \mathrm{~N} / \mathrm{m}

, then its time period, is

View answer and explanation

Correct option: D

2 \pi \sqrt{2}

seconds

Option D (

2 \pi \sqrt{2}

seconds) is correct because the time period of a spring is calculated using the formula

T=2 \pi \sqrt{\frac{m}{k}}

.

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