$\smallint \,\,{e^x}\,\,\frac{{\left( {x - 1} \right)}}{{{x^2}}}\;\,\,dx$ is equal to

$\frac{{{e^x}}}{{{x^2}}}\,\, + \,\,c$

$\frac{{ - \,{e^x}}}{{{x^2}}}\,\, + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \,\,{e^x}\,\,\frac{{\left( {x - 1} \right)}}{{{x^2}}}\;\,\,dx

is equal to

View answer and explanation

Correct option: C

\frac{{{e^x}}}{x}\,\, + \,\,c

Option C (

\frac{{{e^x}}}{x}\, + \,c

) is correct because the integral can be simplified and solved using the property

\int e^x [f(x) + f'(x)] dx = e^x f(x) + c

Practice All Chapter MCQs →

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{C}

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