JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Analyzing +4 | -1

\sec \,\,\theta = \frac{{{a^2} + \,\,{b^2}}}{{{a^2} - \,\,{b^2}}}

, where

a,\,\;b,\, \in R

gives real values of

\theta

if and only if

View answer and explanation

Correct option: B

\left| {\,a\,} \right| \ne \left| {\,b\,} \right| \ne 0

Option B (

\left| {\,a\} \right| \ne \left| {\,b\} \right| \ne 0

) is correct because it ensures that the value of

\sec \theta

is real and either greater than or equal to 1, or less than or equal to -1.

More Questions from TRIGONOMETRY RATIOS

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\tan \alpha=\frac{p}{q}

\alpha=6 \beta

\alpha

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=