JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

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Understanding +4 | -1

The natural domain of the real valued function defined by

f(x)=\sqrt{x^{2}-1}+\sqrt{x^{2}+1}

View answer and explanation

Correct option: D

(-\infty, \infty)-(-1,1)

Option D (

(-\infty, \infty)-(-1,1)

) is correct because

x^2 - 1

must be non-negative for the square root to be real, so

x^2 \ge 1

, which means

x \le -1

x \ge 1

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