Skip to main content
Back to GRAVITATION

JEE PHYSICS MCQ: GRAVITATION

1 Medium
1 of 1
Application +4 | -1
A body of mass MM is divided into two parts of masses mm and (M−m)(M-m). If they are kept at a constant distance, then the relation between mm and MM for maximum force of attraction between them, will be
View answer and explanation
Correct option: D
m=M2m=\frac{M}{2}
Option D (m=M2m=\frac{M}{2}) is correct because the gravitational force is maximized when the product of the two masses is maximized, which occurs when the masses are equal.

More Questions from GRAVITATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.