The enthalpy of atomization of $\mathrm{PH}_3(\mathrm{g})$ is $+954 \mathrm{~kJ} /\mathrm{mol}$ and that of $\mathrm{P}_2 \mathrm{H}_4$ is $+1.488 \mathrm{~MJ} / \mathrm{mol}.$ The bond energy of the $\mathrm{P}-\mathrm{P}$ bond is

$318 \mathrm{~kJ} / \mathrm{mol}$

$372 \mathrm{~kJ} / \mathrm{mol}$

$534 \mathrm{~kJ} / \mathrm{mol}$

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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Analyzing +4 | -1

The enthalpy of atomization of

\mathrm{PH}_3(\mathrm{g})

+954 \mathrm{~kJ} /\mathrm{mol}

and that of

\mathrm{P}_2 \mathrm{H}_4

+1.488 \mathrm{~MJ} / \mathrm{mol}.

The bond energy of the

\mathrm{P}-\mathrm{P}

bond is

View answer and explanation

Correct option: C

216 \mathrm{~kJ} / \mathrm{mol}

Option C (216 kJ/mol) is correct because the bond energy of the P-P bond is calculated by subtracting the energy required to break the P-H bonds in P2H4 from the total enthalpy of atomization and then accounting for the P-H bonds in PH3.

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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