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JEE MATHEMATICS MCQ: FUNCTIONS

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If f:R→Rf:R \to R is defined by f(x)=sin⁡x  and g:(1,  ∞)→Rf\left( x \right) = \sin x\;and\,g:\left( {1,\;\infty } \right) \to R is defined by g(x)=x2−1g\left( x \right) = \sqrt {{x^2} - 1}, then gof(x)gof\left( x \right) is
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Correct option: D
Not defined
Option D (Not defined) is correct because the range of f(x) is not a subset of the domain of g(x), so the composite function gof(x) is not defined.

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