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JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Application +4 | -1
The normal body-temperature of a person is 97∘F97^{\circ} \mathrm{F}. Calculate the rate at which heat is flowing out of his body through the clothes assuming the following values. Room temperature =47∘F=47^{\circ} \mathrm{F}, surface of the body under clothes =1.6 m2,=1.6 \mathrm{~m}^2, conductivity of the cloth =0.04 J s−1 m−1∘C−1=0.04 \mathrm{~J} \mathrm{~s}^{-1} \mathrm{~m}^{-1}{ }^{\circ} \mathrm{C}^{-1}, thickness of the cloth =0.5 cm=0.5 \mathrm{~cm}.
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Correct option: C
356 J/s
Option C (356 J/s) is correct because it applies the formula for heat transfer through conduction, converting Fahrenheit to Celsius correctly.

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