JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

f(x)=\frac{\left(\tan 1^{\circ}\right) x+\log _e(123)}{x \log _e(1234)-\left(\tan 1^{\circ}\right)}, x>0

, then the least value of

f(f(x))+f\left(f\left(\frac{4}{x}\right)\right)

View answer and explanation

Correct option: C

The correct answer is C (2) because f(f(x)) = x, leading to f(f(x)) + f(f(4/x)) = x + 4/x, and the minimum value of x + 4/x for x > 0 is 2.

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