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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
If in a Δ  ABC,  CD\Delta \;ABC,\;CD is the angular bisector of the ∠  ACB\angle \;ACB, then CDCD is equal to
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Correct option: C
2aba+bcos⁡C2\frac{{2ab}}{{a + b}}\cos \frac{C}{2}
Option C (2aba+bcos⁡C2\frac{{2ab}}{{a + b}}\cos \frac{C}{2}) is correct because the length of the angular bisector CD is derived using the area of the triangle.

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