JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Analyzing +4 | -1

Let

X=Y=\mathbf{R} \sim\{1\}

. The function

f: X \rightarrow Y

defined by

f(x)=\frac{x+2}{x-1}

View answer and explanation

Correct option: D

one-one and onto

Option D (one-one and onto) is correct because the function

f(x) = \frac{{x+2}}{{x-1}}

is both injective (one-to-one) and surjective (onto) when

X = Y = \mathbf{{R}} \setminus \{1\}

More Questions from FUNCTIONS

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f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}