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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
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Application +4 | -1
If ω(≠1)\omega(\neq 1) is a cube root of unity, then the value of tan⁡[(ω2017+ω2225)π−π/3]\tan \left[\left(\omega^{2017}+\omega^{2225}\right) \pi-\pi / 3\right]
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Correct option: C
−3-\sqrt{3}
Option C (−3-\sqrt{3}) is correct because it is found by simplifying the expression inside the tangent function using properties of cube roots of unity.

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