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JEE CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

1 Hard
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Analyzing +4 | -1
Assertion : AgI\mathrm{AgI} is coloured while AgF\mathrm{AgF} is colourless.

Reason : Unpaired e−{{\text{e}}^ - } is present in AgI\mathrm{AgI}
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because while AgI is colored and AgF is colorless, the reason is due to charge transfer spectra, not unpaired electrons.

More Questions from CO-ORDINATION COMPOUNDS

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Which has maximum paramagnetic character? Ionization of K[Ag(CN)2]\mathrm{K}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right] will give: The cation that does not form an ammine complex with excess of ammonia is: The complexes [PtCl2(NH3)4]Br2  and  [PtBr2(NH3)4]Cl2  \left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;} are example for isomerism The correct name of [Pt(NH3)4Cl2][PtCl4]\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\left[\mathrm{PtCl}_4\right] is: Which of the following pairs of isomers and types of isomerism are correctly matched?

(I) [Co(NH3)5(NO2)]Cl2\left[{Co}\left({NH}_3\right)_5\left({NO}_2\right)\right] {Cl}_2 and [Co(NH3)5(ONO)]Cl2………\left[{Co}\left({NH}_3\right)_5({ONO})\right] {Cl}_2 \ldots \ldots \ldots Linkage

(II) [Cu(NH3)4][PtCl4]  &  [Pt(NH3)4][CuCl4]………\left[{Cu}\left({NH}_3\right)_4\right]\left[{PtCl}_4\right] \,\, \& \,\, \left[{Pt}\left({NH}_3\right)_4\right]\left[{CuCl}_4\right] \ldots \ldots \ldots Coordinations

(III) [Pt(NH3)4Cl2]Br2  &  [Pt(NH3)4Br2]Cl2………\left[{Pt}\left({NH}_3\right)_4 {Cl}_2\right] {Br}_2 \, \, \& \, \, \left[{Pt}\left({NH}_3\right)_4 {Br}_2\right]{Cl}_2 \ldots \ldots \ldots Ionization

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