JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A body of mass

1.5 \mathrm{~kg}

rotating about an axis with angular velocity of

0.3 \mathrm{rad} \mathrm{s}^{-1}

has the angular momentum of

1.8 \mathrm{~kg}

\mathrm{m}^2 \mathrm{~s}^{-1}

. The radius of gyration of the body about an axis is

View answer and explanation

Correct option: A

2 \mathrm{~m}

Option A (2 m) is correct because it accurately calculates the radius of gyration using the given angular momentum, mass, and angular velocity.

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)