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JEE PHYSICS MCQ: OSCILLATIONS

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A particle hanging from a spring stretches it by 1 cm1 \mathrm{~cm} at earth's surface. Radius of earth is 6400 km6400 \mathrm{~km}. At a place 800 km\mathrm{km} above the earth's surface, the same particle will stretch the spring by:
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Correct option: D
0.79 cm
Option D (0.79 cm) is correct because it is calculated by considering the variation of gravitational force with distance from the Earth's center.

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