JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

The inverse of the function

f:R \to R

given by

f\left( x \right) = {\log _a}\left( {x + \sqrt {{x^2} + 1} } \right)\left( {a > 0,a \ne 1} \right),

View answer and explanation

Correct option: B

\frac{1}{2}\left( {{a^x} - {a^{ - x}}} \right)

Option B (

\frac{1}{2}\left( {{a^x} - {a^{ - x}}} \right)

) is correct because it represents the inverse function of the given logarithmic function.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}