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NEET UG CHEMISTRY MCQ: SOLUTIONS

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The molal elevation constant for water is

\mathrm{0}\mathrm{.52}\;\mathrm{K}\;\mathrm{molalit}{\mathrm{y}^{ - 1}}

. The elevation caused in the boiling point of water by dissolving 0.25 mole of a non-volatile solute in 250 g of water will be :

View answer and explanation

Correct option: C

0.52^\circ \mathrm{C}

Option C is correct because the elevation in boiling point is calculated using the formula

\Delta T_b = K_b \times m

, where m is the molality of the solution.

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Consider the solution of ethanol. In it Assertion: Isotonic solutions don't show net phenomenon of osmosis.

Reason: Isotonic solutions have equal osmotic pressure at constant temperature. 0.2 molal aqueous solution of a monobasic acid is 60% ionised. If Kb for water is

0.52\,K\,kg\,mo{l^{ - 1}}

then the boiling point of the solution will be The vapour pressures of pure liquids

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B

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--{0.93^0}C

{K_f}

1.86\mathrm{ }K\mathrm{ }kg\mathrm{ }mo{l^{ - 1}}

A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300 K. the vapour pressure of propyl alcohol is 200 mm. If the mole fraction of ethyl alcohol is 0.6, its vapour pressure (in mm) at the same temperature will be