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NEET UG PHYSICS MCQ: ATOMS

1 Hard
1 of 1
Application +4 | -1
A 100eV100 \mathrm{eV} electron collides with a stationary helium ion (He+)\left(\mathrm{He}^{+}\right)in its ground state and excites to a higher level. After the collision, He+\mathrm{He}^{+}ions emits two photons in succession with wavelength 1085A∘1085\mathop {\text{A}}\limits^ \circ and 304A∘304\mathop {\text{A}}\limits^ \circ. Also the energy of the electron after the collision is 6×……eV6 \times \ldots \ldots \mathrm{eV} (approximately). Given h=6.63×10−34Js\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}.
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Correct option: A
8
The correct answer is A (8) because after the collision and subsequent photon emissions, the remaining energy of the electron is approximately 8 eV.

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