JEE MATHEMATICS MCQ: TANGENTS & NORMALS

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Application +4 | -1

Equation of normal to the curve

x^2=4 y

which passes through the point

(1,2)

View answer and explanation

Correct option: B

x+y=3

Option B

x+y=3

is correct because by finding the equation of the normal to the curve and using the given point, we can solve for the normal's equation.

More Questions from TANGENTS & NORMALS

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z