JEE CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Analyzing +4 | -1

Which of the following are false about

\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right] \mathrm{SO}_4

?

I. It is paramagnetic with one unpaired electron in the

d

-subshell.

II. Its aqueous solution cannot conduct electricity.

III. It gives white

\mathrm{BaCl}_2

solution.

IV. It is a square planar complex.

Choose the correct option.

View answer and explanation

Correct option: A

I and II

Option A (I and II) is correct because [Cu(NH3)4]SO4 is paramagnetic and its aqueous solution conducts electricity.

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\left[{Co}\left({NH}_3\right)_5({ONO})\right] {Cl}_2 \ldots \ldots \ldots

\left[{Cu}\left({NH}_3\right)_4\right]\left[{PtCl}_4\right] \,\, \& \,\, \left[{Pt}\left({NH}_3\right)_4\right]\left[{CuCl}_4\right] \ldots \ldots \ldots

\left[{Pt}\left({NH}_3\right)_4 {Cl}_2\right] {Br}_2 \, \, \& \, \, \left[{Pt}\left({NH}_3\right)_4 {Br}_2\right]{Cl}_2 \ldots \ldots \ldots