Question

The tungsten filament of an electric lamp has a surface $A$ area and a power rating $P$. If the emissivity of the filament is $\varepsilon $ and $\sigma $ is Stefan&rsquo;s constant, the steady temperature of the filament will be

Accepted Answer

$T = {\left( {\frac{P}{{A\varepsilon \sigma }}} \right)^{\frac{1}{4}}}$

Answer

$T = {\left( {\frac{P}{{A\varepsilon \sigma }}} \right)^4}$

Answer

$T = \left( {\frac{P}{{A\varepsilon \sigma }}} \right)$

Answer

$T = {\left( {\frac{{A\varepsilon \sigma }}{P}} \right)^{\frac{1}{4}}}$

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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