JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

10 \mathrm{~g}

of water at

30^{\circ} \mathrm{C}

and

10 \mathrm{~g}

of ice at

-20^{\circ} \mathrm{C}

are mixed together in a calorimeter. Find the amount of ice that melts. (Specific heat of ice

=0.5 \mathrm{~cal} \mathrm{~g}^{-1}{ }^{\circ} \mathrm{C}

{ }^1

and latent heat of ice

=80 \mathrm{~cal} \mathrm{~g}^{-1}

View answer and explanation

Correct option: A

2.5 g

Option A (2.5 g) is correct because it is the amount of ice that melts when the heat lost by the water is used to first raise the temperature of the ice to 0°C and then melt it.

JEE PHYSICS MCQ: THERMODYNAMICS

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