$\smallint \,\,\frac{{{a^{\sqrt x }}}}{{\sqrt x }}\,\,dx$ is equal to

$\frac{{{a^{\sqrt x }}}}{{\log \,\,a}}\,\, + \,\,C$

$2{a^{\sqrt x }}\,\, \cdot \,\,\log \,\,a\,\, + \,\,C$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \,\,\frac{{{a^{\sqrt x }}}}{{\sqrt x }}\,\,dx

is equal to

View answer and explanation

Correct option: B

\frac{{2{a^{\sqrt x }}}}{{\log \,\,a}}\,\, + \,\,C

The correct answer is B (

\frac{{2{a^{\sqrt x }}}}{{\log \,\,a}}\, + \,\,C

) because after applying the substitution method and integrating, the result matches option B.