JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Medium

1 of 1

Application +4 | -1

A pole indined from vertical at

15^{\circ}

towards the sun. Length of the shadow of the pole is

\sqrt{3}+1

meter at the time when angle of elevation of the sun is

30^{\circ}

, then length of pole is

View answer and explanation

Correct option: B

\frac{\sqrt{2}}{\sqrt{3}-1} m

Option B (

\frac{\sqrt{2}}{\sqrt{3}-1} m

) is correct because it applies the sine rule to the triangle formed by the pole, its shadow, and the sun's rays, accounting for the pole's inclination.

More Questions from PROPERTIES OF TRIANGLES

Practice All Chapter MCQs →

{p_1},{p_2},{p_3}

are altitudes of a

\Delta \;ABC

drawn from the vertices

A,B,C

and

\Delta

the area of the triangle, then

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

is equal to If the sides of the triangles are

5k,\;6k,\;5k

and radius of incircle is 6, the value of

k

is equal to In a

\Delta \,ABC

, if

a = \left( {b - c} \right)\sec \theta

, then

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

is equal to If

\Delta = {a^2} - {\left( {b - c} \right)^2}

, where

\Delta

is the area of

\Delta \;ABC

, then

\tan A

is equal to If

A

is the area and

2 s

is the sum of the sides of a triangle, then