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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy
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Application +4 | -1
If dydx+ytan⁡x=sin⁡2x\frac{d y}{d x}+y \tan x=\sin 2 x and y(0)=1y(0)=1, then y(π)y(\pi) is equal to:
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Correct option: C
-5
Option C (-5) is correct because solving the differential equation and applying the initial condition yields y(π) = -5.

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