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JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1
Let f(x)=(x+1)(x+2)(x+3)….(x+100)f(x)=(x+1)(x+2)(x+3) \ldots .(x+100) and. g(x)=f(x)⋅f′′(x)−(f′(x))2g(x)=f(x) \cdot f^{\prime \prime}(x)-\left(f^{\prime}(x)\right)^2, then g(x)=0g(x)=0, has
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Correct option: A
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Option A (0<x<10 < x < 1) is correct because it satisfies the domain restrictions imposed by the logarithmic functions and the fourth root.

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