JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Analyzing +4 | -1

Potassium chlorate on heating with conc.

{H_2}S{O_4}

gives:

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Correct option: D

All of these

Option D is correct. Potassium chlorate reacts with concentrated sulfuric acid to produce chlorine dioxide, perchloric acid, and potassium bisulfate.

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4